# Ex 9.4, 3 - Chapter 9 Class 12 Differential Equations (Term 2)

Last updated at Dec. 10, 2019 by Teachoo

Last updated at Dec. 10, 2019 by Teachoo

Transcript

Ex 9.4, 3 For each of the differential equations in Exercises 1 to 10, find the general solution : ๐๐ฆ/๐๐ฅ+๐ฆ=1(๐ฆโ 1) ๐๐ฆ/๐๐ฅ+๐ฆ=1 ๐๐ฆ/๐๐ฅ=1โ๐ฆ ๐๐ฆ = (1 โ y) dx ๐๐ฆ/(1 โ ๐ฆ) = dx ๐๐ฆ/(๐ฆ โ 1) = โdx Integrating both sides. โซ1โใ๐๐ฆ/(๐ฆ โ 1)=ใ โซ1โใโ๐๐ฅใ log (y โ 1) = โx + C y โ 1 = e(โx + C) y โ 1 = eโx ร eC y = eโx ร eC + 1 Putting eC = A y = Aeโx + 1 is the general solution

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Ex 9.4, 23 (MCQ)

Chapter 9 Class 12 Differential Equations (Term 2)

Serial order wise

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.